3[z-(9z+21)+5]=5(z+2)

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Solution for 3[z-(9z+21)+5]=5(z+2) equation:


Simplifying
3[z + -1(9z + 21) + 5] = 5(z + 2)

Reorder the terms:
3[z + -1(21 + 9z) + 5] = 5(z + 2)
3[z + (21 * -1 + 9z * -1) + 5] = 5(z + 2)
3[z + (-21 + -9z) + 5] = 5(z + 2)

Reorder the terms:
3[-21 + 5 + z + -9z] = 5(z + 2)

Combine like terms: -21 + 5 = -16
3[-16 + z + -9z] = 5(z + 2)

Combine like terms: z + -9z = -8z
3[-16 + -8z] = 5(z + 2)
[-16 * 3 + -8z * 3] = 5(z + 2)
[-48 + -24z] = 5(z + 2)

Reorder the terms:
-48 + -24z = 5(2 + z)
-48 + -24z = (2 * 5 + z * 5)
-48 + -24z = (10 + 5z)

Solving
-48 + -24z = 10 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
-48 + -24z + -5z = 10 + 5z + -5z

Combine like terms: -24z + -5z = -29z
-48 + -29z = 10 + 5z + -5z

Combine like terms: 5z + -5z = 0
-48 + -29z = 10 + 0
-48 + -29z = 10

Add '48' to each side of the equation.
-48 + 48 + -29z = 10 + 48

Combine like terms: -48 + 48 = 0
0 + -29z = 10 + 48
-29z = 10 + 48

Combine like terms: 10 + 48 = 58
-29z = 58

Divide each side by '-29'.
z = -2

Simplifying
z = -2

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